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墨爾本代寫essay案例:How will the Digital Systems ass

How will the Digital Systems assignment will be marked?
A: Q1.1 悉尼代寫Assessment Q3.1 4 marks, all other parts are worth 2 marks each, giving a total of 20 marks.
Q How do I stop Quartus from overriding my state assignment 悉尼代寫Assessment using more flip-flops ("registers" in Quartus)?

A:  Go to menu Assignments ->Settings->Analysis 悉尼代寫Assessment Synthesis Settings->More Settings->State Machine processing, 悉尼代寫Assessment change to User-Encoded .  See the following dialogue box:

 

Q
In the Question 1 悉尼代寫Assessment Question 2 of the assignment, it asks 悉尼代寫Assessment using 5 flip flops. So, do we have to implement Moore FSM by using only combinational logics, or we could use "case" instructions ?
A:
1  A FSM cannot be implemented with just combinational logic since it is a sequential circuit.  However if you separate out the state flip-flops, the remaining logic can be combinational.   The state flip-flops can be created from an always block - using instantiation of separate flip-flops is inefficient 悉尼代寫Assessment not necessary.
2.  Case statements can result in combinational or sequential logic on synthesis, depending on how they are used.  A combinational circuit results from all input combinations being covered in the always block 悉尼代寫Assessment no posedge conditions in the sensitivity list of the always block.  Here is an example if a combinational use of a case statement :

module hexdisplay(binary, hex);
input [3:0] binary;
output reg [6:0] hex;
always @(binary)
  case (binary)
    0: hex <= 7'b 1000000;
    1: hex <= 7'b 1111001;
    2: hex <= 7'b 0100100;
    3: hex <= 7'b 0110000;
    4: hex <= 7'b 0011001;
    5: hex <= 7'b 0010010;
    6: hex <= 7'b 0000010;
    7: hex <= 7'b 1111000;
    8: hex <= 7'b 0000000;
    9: hex <= 7'b 0011000;
    default: hex <= 7'b 1111111;
  endcase
<标题> endmodule

<标题> Here is an example from the lectures of a sequential circuit from a case statement with 3 flip-flops inferred

module string_recog_FSM(Clk, X, reset, Z);
   output Z;
   input Clk, X, reset;
   reg state[0:2];
   parameter S0 = 3’b000; // reset state
   parameter S1 = 3’b001; // strings ending in …0
   parameter S2 = 3’b010; // strings ending in …01
   parameter S3 = 3’b011; // strings ending in …010
   parameter S4 = 3’b100; // strings ending in …1
   parameter S5 = 3’b101; // strings ending in …10
   parameter S6 = 3’b110; // strings ending in …100

   assign Z = (state == S3);

   always @(posedge Clk)
      if (Reset) state = S0;
      else case(state)
       S0: if (X) state = S4 else state = S1;
       S1: if (X) state = S2 else state = S1;
       S2: if (X) state = S4 else state = S3;
       S3: if (X) state = S2 else state = S6;
       S4: if (X) state = S4 else state = S5;
       S5: if (X) state = S2 else state = S6;
       S6: state = S6;
       default:   state = 3’bxxx;
      endcase
<标题> endmodule

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