﻿ 墨尔本代写essay案例：How will the Digital Systems ass-澳洲代写,悉尼代写,堪培拉代写,墨尔本代写

# 墨爾本代寫essay案例：How will the Digital Systems ass

How will the Digital Systems assignment will be marked?
A: Q1.1 悉尼代寫Assessment Q3.1 4 marks, all other parts are worth 2 marks each, giving a total of 20 marks.
Q How do I stop Quartus from overriding my state assignment 悉尼代寫Assessment using more flip-flops ("registers" in Quartus)?

<标题> A:  Go to menu Assignments ->Settings->Analysis 悉尼代寫Assessment Synthesis Settings->More Settings->State Machine processing, 悉尼代寫Assessment change to User-Encoded .  See the following dialogue box:

Q
In the Question 1 悉尼代寫Assessment Question 2 of the assignment, it asks 悉尼代寫Assessment using 5 flip flops. So, do we have to implement Moore FSM by using only combinational logics, or we could use "case" instructions ?
A:
1  A FSM cannot be implemented with just combinational logic since it is a sequential circuit.  However if you separate out the state flip-flops, the remaining logic can be combinational.   The state flip-flops can be created from an always block - using instantiation of separate flip-flops is inefficient 悉尼代寫Assessment not necessary.
2.  Case statements can result in combinational or sequential logic on synthesis, depending on how they are used.  A combinational circuit results from all input combinations being covered in the always block 悉尼代寫Assessment no posedge conditions in the sensitivity list of the always block.  Here is an example if a combinational use of a case statement :

module hexdisplay(binary, hex);
input [3:0] binary;
output reg [6:0] hex;
always @(binary)
case (binary)
0: hex <= 7'b 1000000;
1: hex <= 7'b 1111001;
2: hex <= 7'b 0100100;
3: hex <= 7'b 0110000;
4: hex <= 7'b 0011001;
5: hex <= 7'b 0010010;
6: hex <= 7'b 0000010;
7: hex <= 7'b 1111000;
8: hex <= 7'b 0000000;
9: hex <= 7'b 0011000;
default: hex <= 7'b 1111111;
endcase
endmodule

Here is an example from the lectures of a sequential circuit from a case statement with 3 flip-flops inferred

module string_recog_FSM(Clk, X, reset, Z);
output Z;
input Clk, X, reset;
reg state[0:2];
parameter S0 = 3’b000; // reset state
parameter S1 = 3’b001; // strings ending in …0
parameter S2 = 3’b010; // strings ending in …01
parameter S3 = 3’b011; // strings ending in …010
parameter S4 = 3’b100; // strings ending in …1
parameter S5 = 3’b101; // strings ending in …10
<标题>    parameter S6 = 3’b110; // strings ending in …100

assign Z = (state == S3);

always @(posedge Clk)
if (Reset) state = S0;
else case(state)
S0: if (X) state = S4 else state = S1;
S1: if (X) state = S2 else state = S1;
S2: if (X) state = S4 else state = S3;
S3: if (X) state = S2 else state = S6;
S4: if (X) state = S4 else state = S5;
S5: if (X) state = S2 else state = S6;
S6: state = S6;
default:   state = 3’bxxx;
endcase
endmodule

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